Make a frequency distribution table with five classes.
Minutes Spent on the Phone
Construct a Frequency Distribution
Minimum = 67, Maximum = 125
Number of classes = 5
Class width = 12
3
5
8
9
5
Midpoint
Relative
Frequency
Class
72.5
84.5
96.5
108.5
120.5
0.10
0.17
0.27
0.30
0.17
3
8
16
25
30
Other Information
Cumulative
Frequency
Class boundaries - numbers that separate classes without forming gaps between them
Frequency Histogram
Time on Phone
minutes
Class
67 - 78
79 - 90
91 - 102
103 -114
115 -126
3
5
8
9
5
3
5
8
9
5
72.5
84.5
96.5
108.5
120.5
Mark the midpoint at the top of each bar. Connect consecutive midpoints. Extend the frequency polygon to the axis.
Cumulative Frequency
minutes
Minutes on Phone
-contains all original data
-easy way to sort data & identify outliers
Minutes Spent on the Phone
Key values:
Minimum value =
Maximum value =
67
125
Lowest value is 67 and highest value is 125, so list stems from 6 to 12.
Never skip stems. You can have a stem with NO leaves.
Stem
Leaf
12 |
11 |
10 |
9 |
8 |
7 |
6 |
Stem
Leaf
Stem-and-Leaf Plot
Key: 6 | 7 means 67
Key: 6 | 7 means 67
1st line digits 0 1 2 3 4
2nd line digits 5 6 7 8 9
1st line digits 0 1 2 3 4
2nd line digits 5 6 7 8 9
minutes
Used to describe parts of a whole
Central Angle for each segment
Construct a pie chart for the data.
Human Space Flight 5.7
Technology 5.9
Mission Support 2.7
Billions of $
Median: The point at which an equal number of values fall above and fall below
Mode: The value with the highest frequency
Calculate the mean, the median, and the mode
An instructor recorded the average number of absences for his students in one semester. For a random sample the data are:
2 4 2 0 40 2 4 3 6
Calculate the mean, the median, and the mode
Mean:
Median: Sort data in order
The middle value is 3, so the median is 3.
Mode: The mode is 2 since it occurs the most times.
An instructor recorded the average number of absences for his students in one semester. For a random sample the data are:
Calculate the mean, the median, and the mode.
2 4 2 0 2 4 3 6
Suppose the student with 40 absences is dropped from the course. Calculate the mean, median and mode of the remaining values. Compare the effect of the change to each type of average.
The middle values are 2 and 3, so the median is 2.5.
0 2 2 2 3 4 4 6
Calculate the mean, the median, and the mode.
Mean:
2 4 2 0 2 4 3 6
Suppose the student with 40 absences is dropped from the course. Calculate the mean, median and mode of the remaining values. Compare the effect of the change to each type of average.
Mean > Median
Mean < Median
Shapes of Distributions
Weighted Mean
Mean of Grouped Data
56 33
56 42
57 48
58 52
61 57
63 67
63 67
67 77
67 82
67 90
Stock A
Stock B
Two Data Sets
Mean = 61.5
Median = 62
Mode = 67
Mean = 61.5
Median = 62
Mode = 67
56 33
56 42
57 48
58 52
61 57
63 67
63 67
67 77
67 82
67 90
Stock A
Stock B
Two Data Sets
Range for B = 90 – 33 = $57
The range is easy to compute but only uses two numbers from a data set.
Measures of Variation
In a population, the deviation for each value x is:
Measures of Variation
To calculate measures of variation that use every value in the data set, you need to know about deviations.
In a sample, the deviation for each value x is:
58 – 61.5
Stock A
Deviation
The sum of the deviations is always zero.
(
)2
The population standard deviation is $4.34.
The sample standard deviation, s, is found by taking the square root of the sample variance.
About 99.7% of the data lies within 3 standard deviations of the mean
About 95% of the data lies within 2 standard deviations of the mean
–4
–3
–2
–1
0
1
2
3
4
Empirical Rule (68-95-99.7%)
13.5%
13.5%
2.35%
2.35%
Using the Empirical Rule
Using the Empirical Rule
$120,000 is 1 standard deviation below
the mean and $135,000 is 2 standard
deviations above the mean.
68% + 13.5% = 81.5%
So, 81.5% have a value between $120 and $135 thousand.
For any distribution regardless of shape the portion of data lying within k standard deviations (k > 1) of the mean is at least 1 – 1/k2.
For k = 2, at least 1 – 1/4 = 3/4 or 75% of the data lie
within 2 standard deviation of the mean. At least 75% of the data is between -1.68 and 13.68.
52.4
54.6
56.8
59
50.2
48
45.8
2 standard deviations
At least 75% of the women’s 400-meter dash times will fall between 48 and 56.8 seconds.
Mark a number line in
standard deviation units.
A
See example on pg 82
f is the frequency, n is total frequency,
x is the midpoint, f is the frequency, n is total frequency
See example on pg 83
Quartiles
Quartiles
The median = Q2 = 42.
There are 13 values above/below the median.
Q1 is 30.
Q3 is 45.
Finding Quartiles
Interquartile Range (IQR)
Q1
Q2 = the median
Q3
Minimum value
Maximum value
30
42
45
17
55
42
45
30
17
55
Interquartile Range = 45 – 30 = 15
A 63rd percentile score indicates that score is greater than or equal to 63% of the scores and less than or equal to 37% of the scores.
P50 = Q2 = the median
P25 = Q1
P75 = Q3
Cumulative distributions can be used to find percentiles.
A value of x = 148 is 0.57 standard deviations below the mean.
A value of x = 152 is equal to the mean.
Calculations of z-Scores
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